Activity 11
MATH 216: Statistical Thinking
Continuous Random Variables: Uniform Distribution
Time Allocation: 15 minutes total (5 min reading, 10 min individual work)
Part 1: Conceptual Understanding (3 minutes)
Instructions: Answer the following questions about continuous random variables:
- Why is the probability of a continuous random variable taking on a specific value always zero?
- How does the area under a probability density function (PDF) curve relate to probability?
- What is the key difference between probability mass functions (for discrete variables) and probability density functions (for continuous variables)?
Part 2: Uniform Distribution Calculations (4 minutes)
Scenario: Suppose X is uniformly distributed between a = 2 and b = 8.
Instructions: Use the uniform distribution formulas to calculate:
\(P(3 \leq X \leq 5)\) = \((d-c)/(b-a)\) =
Mean (\(\mu\)) = \((a+b)/2\) =
Variance (\(\sigma^2\)) = \((b-a)^2/12\) =
Standard Deviation (\(\sigma\)) = \(\sqrt{\sigma^2}\) =
Show your work for at least two calculations:
Part 3: Real-World Application (3 minutes)
Scenario: An unprincipled used-car dealer sells a car with a known major breakdown risk within the next 6 months. The dealer provides a 45-day warranty. Let \(X\) represent the time until breakdown (in months), uniformly distributed between 0 and 6 months.
Calculate:
- Mean time until breakdown: months
- Standard deviation: months
- Probability breakdown occurs during warranty (45 days = 1.5 months):
Critical Thinking: Why might this uniform distribution assumption be unrealistic for car breakdown times?