Activity 28
MATH 216: Statistical Thinking
Paired t-Test Framework
Time Allocation: 15 minutes total (5 min reading, 10 min individual work)
Part 1: Conceptual Understanding (3 minutes)
Instructions: Answer the following questions based on the lecture content:
- What is the key advantage of using paired data in statistical comparisons, and how does this affect the test statistic calculation?
- Explain the difference between the null and alternative hypotheses in a paired t-test context, and why we focus on mean differences rather than individual group means.
- What are the key assumptions for valid paired t-test inference, and how do we check these assumptions in practice?
Part 2: Real-World Paired Testing Applications (4 minutes)
Apply paired t-test framework to real-world scenarios:
Right-Tailed Test - Medical Study: Testing if new drug increases blood pressure (\(n=15\))
- Before: 120, 118, 122, 119, 121, 117, 123, 119, 120, 118, 121, 119, 122, 120, 118
- After: 125, 122, 128, 124, 126, 120, 130, 125, 127, 123, 129, 124, 128, 126, 122
- Test \(H_a: \mu_d > 0\) (drug increases blood pressure)
- Calculate mean difference and t-statistic
\(\bar{d}\) = , t-statistic =
Two-Tailed Test - Educational Research: Testing if teaching method affects test scores (\(n=12\))
- Traditional: 78, 82, 85, 79, 88, 81, 83, 86, 80, 84, 87, 82
- New Method: 85, 88, 90, 83, 92, 86, 89, 91, 84, 87, 93, 88
- Test \(H_a: \mu_d \neq 0\) (methods differ)
- Calculate mean difference and t-statistic
\(\bar{d}\) = , t-statistic =
Training Program Comparison: Testing effectiveness of two training methods (\(n=20\))
- Method A: 85, 88, 90, 92, 91, 89, 93, 95, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107
- Method B: 83, 89, 87, 84, 92, 90, 85, 91, 98, 94, 100, 101, 99, 111, 111, 106, 109, 103, 111, 114
- Test \(H_a: \mu_d > 0\) (Method A better than Method B)
- Calculate mean difference and t-statistic
\(\bar{d}\) = , t-statistic =
Show your work for one complete calculation:
Part 3: Decision Making and Interpretation (3 minutes)
Make statistical decisions and interpret paired test results:
- For the medical study case (\(\bar{d} = 4.8\), t = 8.85, critical = 1.761), what is your statistical conclusion? What are the clinical implications of this finding?
- For the educational research case (\(\bar{d} = 4.3\), t = 8.27, critical = 2.201), what is your statistical conclusion? What does this mean for educational practice?
- For the training program comparison (\(\bar{d} = 3.2\), t = 2.15, critical = 1.729), what is your statistical conclusion? What are the practical implications for training program selection?